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length needed?

Pythagorean equation
(height to door from ground) squared + (distance from barn)squared = (the length of conveyor needed)squared. So do the square root of the answer to find the length needed.
 
Take a rope nail it to the door opening,drop it down, mark it with tape ,go back up and undo rope,measure between, There you go,problem solved.No hypotenuse of the right triangle needed.
This will help.LOL. If you don't want to crawl up and down,take rope premeasure,tie to an arrow,shoot it into barn wood,record measurement,no extra steps up and down.LOL
Regards,LOU & VICTOR
 
Remember when you were in HS and you said "I don't need to learn this stuff. What good will it do me?" Here's the trig you never learned LOL
 
As I recall, my bale elevator is about 22' long to get bales up into a 10' high loft. 24' would be better. I'm not sure I'd want to go less than 20'. That 1/2 hp motor on mine has a little trouble getting bales up to steep a slope. I probably need a bigger motor or change the pulleys but I may be as small as I can go on the motor. Sometimes a bale hangs up on the side and I need to give it a shove.
 
Yeah,
Remember that math stuff from high school 40 years ago BUT I was wondering how to get the HEY in the MOW now!

Sorry - Couldn't resist on a tractor board.
 
A conveyor at a 45 degree angle should work fine. Others will too, but 45 is common. Measure ground to haymow, figure the same distance away from the barn. From that point from the barn, to the haymow discharge level, is 45 degrees. Vertical distance is "A", horizontal distance is "B". "A" squared times "B" squared equals "C" squared- that is the Pythagorean theorem. So, if A is 25 feet, and B is 25 feet (45 degree angle)- "C"squared is 35.35 feet. If you go to a steeper angle, you need a stronger motor to do the same job.
 

You won't like 45*..bales sometimes will rear up and tumble back..
Less angle would be much preferred..

Also, figure 8-10 feet more length to make work easier for the men working in the mow..
Ours was a McCurdy 48' and was about perfect for grain, ear corn and hay bales..
about 8 HP Wisconsin engine..
Ron..
 
lou's got it, since we don't know how high your loft door is above the ground nobody can tell you the actual length of conveyor, also any slope going away from the barn will make the nessessary length longer, get a rope and fasten it to the loft, then string it out to a workable angle on the ground, 45* is too steep, thats the "angle or repose" for most material ie gravel, dry dirt, rock, so try for less angle, hay aint dirt and may not fall back, but why worry about having to dodge bales for the next 20 years?
 
At 45* the bales will roll over backward trying to go up the slope, the shorter the bale the worse the problem is. Try for a 30* angle and as said have enough length to reach in the barn aways. The rope from the door out is a good idea and with that you can get a good idea of the angle you are getting but remember to add the length in the barn.
 
On second thought, I agree that 45 is too steep. The one I built was 40 feet long, and delivered bales to a mow conveyor about 25 feet above ground. Also the base of the lower conveyor was on pipe supports about 4 feet above ground, to make unloading wagons easier.
 
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